npm init [--force|-f|--yes|-y|--scope]
npm init <@scope> (same as `npx <@scope>/create`)
npm init [<@scope>/]<name> (same as `npx [<@scope>/]create-<name>`)
Create a new React-based project using create-react-app:
$ npm init react-app ./my-react-app
Create a new esm-compatible package using create-esm:
$ mkdir my-esm-lib && cd my-esm-lib
$ npm init esm --yes
Generate a plain old package.json using legacy init:
$ mkdir my-npm-pkg && cd my-npm-pkg
$ git init
$ npm init
Generate it without having it ask any questions:
$ npm init -y
npm init <initializer> can be used to set up a new or existing npm package.
initializer in this case is an npm package named create-<initializer>, which
will be installed by npx, and then have its main bin
executed -- presumably creating or updating package.json and running any other
initialization-related operations.
The init command is transformed to a corresponding npx operation as follows:
npm init foo -> npx create-foonpm init @usr/foo -> npx @usr/create-foonpm init @usr -> npx @usr/createAny additional options will be passed directly to the command, so npm init foo --hello will map to npx create-foo --hello.
If the initializer is omitted (by just calling npm init), init will fall back
to legacy init behavior. It will ask you a bunch of questions, and then write a
package.json for you. It will attempt to make reasonable guesses based on
existing fields, dependencies, and options selected. It is strictly additive, so
it will keep any fields and values that were already set. You can also use
-y/--yes to skip the questionnaire altogether. If you pass --scope, it
will create a scoped package.
Last modified October 26, 1985 Found a typo? Send a pull request!